1/5(x+20)^2=9x+230

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Solution for 1/5(x+20)^2=9x+230 equation: 



1/5(x+20)^2=9x+230

We move all terms to the left:

1/5(x+20)^2-(9x+230)=0



Domain of the equation: 5(x+20)^2!=0

x∈R



We get rid of parentheses

1/5(x+20)^2-9x-230=0

We multiply all the terms by the denominator


-9x*5(x+20)^2-230*5(x+20)^2+1=0

Wy multiply elements

-45x^2(x-1150x(x+1=0

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